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数据库关联查询语句

数据库里面的记录是没有什么顺序可言的,只有经过一定方法的排序之后才可以有顺序,所以不存在表中第二行数据这个说法.所以如果以一个主键为排序方式的话,可以用如下方法: select top 1 * from record where (not (排序字段 in (select top 1 排序字段 from record))) 虽然看起来有点逻辑不通,但是确实能实现那种要求. sql2000下测试通过

哈哈select t.*,Connect_by_root id as root from (select 1 as bh, 'C' as id, 'A' as oldid from dualunion allselect 2 as bh, 'B' as id, 'Y' as oldid from dualunion allselect 3 as bh, 'X' as id, 'H' as oldid from dualunion allselect 4 as bh, 'A' as id, 'B' as oldid from dual) t start with id='C'connect by prior oldid=id

select name from tab1 union allselect name from tab2

日志表加个userid关联字段 然后查询语句:select diraty_id,diraty_title,diraty_content inner join person on person.userid=diraty.userid and person.userid=登录用户的id insert语句就不用我写了把

select 名字 from a,bwhere a.id = b.aidand b.名字 = "bob"你说的太乱了 给你个类似形式,自己补充吧a.id = b.aid就是把a,b两个表相同的列关联起来,然后再找b表中名字为bob的 也就是and后面的条件

select plan from table2 where id= select id from table1 where card=''

SELECT * FROM A,B where B.Id in(A.bides) and A.id=1order by B.id desc 这样可正常运行,但一次只显示不条记录,并不能循环获取!! 对我有用[0]丢个板砖[0]引用举报管理TOPxyflash3(xyflash3)等 级:

比如:select a.datecol,sum(b.sum) sum from a,b where a.id = b.fid group by a.datecol

例如: select books.id,books.title,books.author,categories.name from books,catgories where books=publisherid=catgories.id

select uid,user,userinfo, name, score from 表1 left join (select uid,name,max(score) from 表2 group by 表2.uid) b on 表1.uid = b.uid

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